In a parallelogram PQRS angle P=40° more then angle Q. Find the angles of the parallelogram .
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In parallelogram PQRS
PS || RQ
ATQ
Angle P = 40 + Angle Q
Let angle Q = x
angle P = 40 + x
AngleQ+angleP= 180 [ PS||RQ]
x + 40+x = 180
2x = 140
x = 70
=> angle Q = 70
angle P = 70 + 40 = 110
Hope it helps !
PS || RQ
ATQ
Angle P = 40 + Angle Q
Let angle Q = x
angle P = 40 + x
AngleQ+angleP= 180 [ PS||RQ]
x + 40+x = 180
2x = 140
x = 70
=> angle Q = 70
angle P = 70 + 40 = 110
Hope it helps !
parneetkaur5454:
Sorry I frorgot to type the last part
Here it is
As PQRS is a parallelogram Therefore angle P = angle R and Angle Q = angle S
Therefore angle R = 110 degree and angle S = 70 degree
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