Question

in a parallelogram pqrs if angle P=(3x-5) and angle Q(2x+15).Find the value of x

Answer 1

Angle P + Angle Q = 180.

3x-5 + 2x+15 = 180

5x + 10 = 180

5x = 170

x = 34.

Answer 2

Given:

In a parallelogram PQRS, angle P=(3x-5) and angle Q(2x+15).

To find:

The value of x.

Solution:

The value of x is 34.

To answer this question, first of all, we should know that in a parallelogram ABCD having angles angle A, angle B, angle C and angle D, the sum of adjacent angles is equal to 180°.

This means,

angle A + angle B = 180°

angle B + angle C = 180°

angle C + angle D = 180°

and

angle A + angle D = 180°

So,

according to the question, we have,

In a parallelogram PQRS,

angle P = (3x - 5)°

angle Q = (2x + 15)°

So,

angle P + angle Q = 180° (adjacent angles property)

Thus,

$3x - 5 + 2x + 15 = 180$

On solving the above, we get,

$5x + 10 = 180$

$5x = 170$

$x = 34$

Hence, the value of x is 34.