In a parallelogram pqrs, if angle p = (3x-5) degree and angle q = (2x+15) degree. Find the value of x
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Answer:
Angle P+ Angle Q=180°
3x-5°+2x+15°=180°
5x+10°=180°
5x=180°-10°
x=170°/5
x=34°
Answered by
1
angle p+ angle q=180° (co interior angles)
3x-5+2x+15=180°
5x+10=180°
5x=180-10
5x=170°
x=170/5
x=34°
3x-5+2x+15=180°
5x+10=180°
5x=180-10
5x=170°
x=170/5
x=34°
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