Question

In a parallelogram PQRS, if <P = (3x-5) and<Q = ( 2x + 15). Find the value of x.

Answer 1

PQRS is a parellogram so,
<p +<q=180°
(3x-5)+(2x+15)=180°
5x+10=180
5x=170
x=170/5=34

Answer 2

Answer:

x = 34

Step-by-step explanation:

We are given a parallelogram PQRS

$\angle P = (3x-5)$

$\angle Q = (2x+15)$

Property of Parallelogram : Sum of consecutive angles of parallelogram is 180°

So, $\angle P +\angle Q = 180^{\circ}$

$2x+15+3x-5 = 180^{\circ}$

$5x+10 = 180$

$5x=170$

$x=34$

Hence the value of x is 34 .