Question

In a parallelogram PQRS, if ∠P = (3x − 5)° and ∠Q = (2x + 15)°, then find the value of x.

Answer 1

Answer:

$\large \star\: \sf \fbox \red{Given - }$

$\sf \: ∠P = (3x − 5)°$

$\sf \: ∠Q = (2x + 15)°$

$\large \star\: \sf \fbox \red{solution - }$

$\sf \: we \: know \: that$

$\sf \blue\: parallelogram \:adjacent \: angles \: are \\ \sf \: supplymentry$

$\sf \: ∠p \: + \: ∠q \: = \: 180\degree$

$\therefore\sf (3x - 5) + (2x + 15) = 180$

$\therefore \sf \: (5x - 10) = 180$

$\therefore \sf \: 5x = 180 + 10$

$\therefore \sf \: 5x = 190$

$\sf \therefore \: x = \frac{190}{5}$

$\sf \therefore \: x = 38 \degree$

Hope it's helpful

Answer 2

We know in parallelogram adjacent angles are supplementary.

.

. . /_ p + /_q = 180°

=》( 3x -5 ) + ( 2x + 15) = 180°

=》(5 x -10) = 180°

=》5x = 180 + 10 °

=》5x = 190°

=》x = 190 ÷ 5°

= 38°

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