Question

In a parallelogram PQRS , M and N are points on pq and RS such that PM = RN prove that MS || NQ

Answer 1

To prove MS II NQ
PROOF: In triangle PMS and triangle RNQ
angle MPS =angle NRQ ( opp. angle of IIgram)
PS = RQ ( opp. sides of IIgram)
PM =RN (given)
therefore , ∆PMS =∆RNQ ( by S.A.S)
MS = NQ ( by c.p.c.t.)
Now as PQ IIRS SO MQ II SN ( as MQ is a part of PQ and SN is of RS
NOW , as in quad. MQSN MQ II SN and MS = NQ
Therefore MQSN is a IIgram
therefore , MS II NQ
H. P.

Answer 2

Step-by-step explanation:

prove both triangle congruent

then cpct

rs =pq

thus it's parallelogram