In a parallelogram pqrs, one is 90 degre. If all the other angle are equal, find them.
Answers
Answered by
8
Let the angles be P,Q,R,S.
And angle P be 90 degrees.
According to the given condition
Angle Q = Angle R = Angle S.
As we know that sum of all angles of a quadrilateral is 360 degrees.
Therefore
Angle P + Angle Q + Angle R + Angle S = 360
90 + Q + Q + Q = 360
3Q = 270
Q = 90
Therefore R = 90 and S = 90.
And angle P be 90 degrees.
According to the given condition
Angle Q = Angle R = Angle S.
As we know that sum of all angles of a quadrilateral is 360 degrees.
Therefore
Angle P + Angle Q + Angle R + Angle S = 360
90 + Q + Q + Q = 360
3Q = 270
Q = 90
Therefore R = 90 and S = 90.
Answered by
6
Given angle =>p, q, r, s
So
According to the question
One is of 90 °
So
Let the
P=>90
Then
All left Angle are equal
So
Let the angle q, r, s=>x
So
90+x+x+x=360 ( sum of a quadrilateral)
90+3x=360
3x=360-90
3x=270
X=270/3
X=90
So
1 angle =>90
2angle =>90
3 angle =>90
4 angle=>90
I hope this will help you
By DEVANSH
So
According to the question
One is of 90 °
So
Let the
P=>90
Then
All left Angle are equal
So
Let the angle q, r, s=>x
So
90+x+x+x=360 ( sum of a quadrilateral)
90+3x=360
3x=360-90
3x=270
X=270/3
X=90
So
1 angle =>90
2angle =>90
3 angle =>90
4 angle=>90
I hope this will help you
By DEVANSH
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