Math, asked by s1856sumit6839, 4 days ago

In a parallelogram PQRS, ∠P= (3 − 5)° ∠Q=(2 + 15)°. Find the value of .​

Answers

Answered by manshakochhar2004
1

Step-by-step explanation:

The value of x is 34.

To answer this question, first of all, we should know that in a parallelogram ABCD having angles angle A, angle B, angle C and angle D, the sum of adjacent angles is equal to 180°.

This means,

angle A + angle B = 180°

angle B + angle C = 180°

angle C + angle D = 180°

and

angle A + angle D = 180°

So,

according to the question, we have,

In a parallelogram PQRS,

angle P = (3x - 5)°

angle Q = (2x + 15)°

So,

angle P + angle Q = 180° (adjacent angles property)

Thus,

3x - 5 + 2x + 15 = 1803x−5+2x+15=180

On solving the above, we get,

5x + 10 = 1805x+10=180

5x = 1705x=170

x = 34x=34

Hence, the value of x is 34

please mark as BRAINLIEST

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