Question

In a parallelogram PQRS. PT and QT are angular bisectors of angle P and angle Q then angle PTQ is
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Answer 1

Answer:

the angle PTQ is 90degree I hope it will help you

Answer 2

Given: the angle bisectors of ∠P and ∠Q are PT and QT, respectively.

To find: the measure of ∠PTQ.

Step-by-step explanation:

Step 1 of 2

The sum of adjacent angles pf a parallelogram is 180°.

⇒ ∠P+∠Q=180°                    

The angle bisector divides the angle in two equal parts.

⇒ ∠SPT=∠TPQ and ∠RQP=∠TQP.

As ∠P+∠Q=180°.

∠SPT+∠TPQ+∠RQP+∠TQP=180°.

2∠TPQ+2∠TQP=180°.

∠TPQ+∠TQP=90°.

Step 2 of 2

Applying triangle sum property in ΔPTQ.

∠TPQ+∠TQP+∠PTQ=180°

90°+∠PTQ=180°

∠PTQ=180°-90°

∠PTQ=90°.