Question

In a parallelogram, PQRS taken in order, if angle Q = 128º, determine the measures of its other angles.​

Answer 1

Let the ABCD is a quadrilateral witch ∠A,∠B,∠Cand∠D in ratio 3:7:6:4

Sum of ratio 3+7+6+4=20

∠A+∠B+∠C+∠D=360

0

∴∠A=

20

3

×360=54

0

∴∠B=

20

7

×360=126

0

∴∠c=

20

6

×360=108

0

∴∠D=

20

4

×360=72

0

Then ABCD is a quadrilateral is trapezium

Answer 2

Answer:

52°,128°,52°128°

Step-by-step explanation:

Given ,

/_Q= 128°

PQRS is a parallelogram.

2 sides of parallelogram are 128°. Let other two sides be x

x.

By using angle sum property

$sum \: of \: all \: angles \: in \: a \: quadrilateral \: = 360$

128+128+x+x = 360

256+2x =360

2x = 104

x= 52°

52° ,128°,52°,128° are angles of paralleogram.