In a parallelogram PQRS, the bisectors of angle P and
angle S intersect at M. What is the measure of angle PMS?
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Answer:
PQRS is a parallelogram.
PO is angle bisector of ∠P
∴ ∠SPO=∠OPQ --- ( 1 )
QO is an angle bisector of ∠Q
∴ ∠RQO=∠OQP ---- ( 2 )
∴ PS∥QR
⇒ ∠SPQ+∠PQR=180o [ Sum of adjacent angles are supplementary ]
⇒ ∠SPO+∠OPQ+∠OQP+∠OQR=180o
⇒ 2∠OPQ+2∠OQP=180o [ From ( 1 ) and ( 2 ) ]
⇒ ∠OPQ+∠OQP=90o ---- ( 3 )
Now, in △POQ,
⇒ ∠OPQ+∠OQP+∠POQ=180o.
⇒ 90o+∠POQ=180o [ From ( 3 ) ]
⇒ ∠POQ=90o.
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