Question

In a parallelogram PQRS, the bisectors of angle P and angleQ meet at O. Find angle POQ.
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Answer 1

Step-by-step explanation:

question acha h mujhe aata h par tumhe ni lagta ki points thode kam h

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Given that:

∠SPO=∠OPQ∠SPO=∠OPQ and ∠RQO=∠OQP.∠RQO=∠OQP.

∠P+∠Q=180∘∠P+∠Q=180∘         [Since PS∥QRSince PS∥QR]

12(∠P+∠Q)=180∘212(∠P+∠Q)=180∘2

∠OPQ+∠OQP=90∘∠OPQ+∠OQP=90∘               ......(1)

Now, 

In △PQO,△PQO,

∠OPQ+∠OQP+∠POQ=180∘∠OPQ+∠OQP+∠POQ=180∘

∠POQ=90∘∠POQ=90∘                       [From equation (1)]

∠O=90∘.∠O=90∘.     

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