In a parallelogram pqrs,the bisectos of angle Pand angleQ Meet at O. Find angle POQ..
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Angle P+angle Q=180
Therefore 1/2angleP+1/2angleQ=90
AngleQPO+AnglePQO+AnglePOQ=180
90+AnglePOQ=180
Angle POQ=180-90
Therefore angle POQ=90
Therefore 1/2angleP+1/2angleQ=90
AngleQPO+AnglePQO+AnglePOQ=180
90+AnglePOQ=180
Angle POQ=180-90
Therefore angle POQ=90
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HI shivam
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this is the answer for your question.
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