Question

In a parallelogram RING, if m<R = 70°,find all the other angles.
​

Answer 1

$\huge \mathtt{GivEn:-}$

• RING is a parallelogram.
• m<R = 70°

$\large \mathtt{NeEd \: tO \: fiNd:-}$

• All the other angles of parallelogram.

$\large \underline{ \mathtt{ \red{ \: ExplaNatiOn:-}}}$

As it given that;

$\large{ \implies}$ m<R = 70°

$\large{\bold{ \mathtt{Therefore,}}}$

$\large{ \implies}$ m<N = 70° [<R and <N are opposite angles of a parallelogram]

Since, <R and <I are supplementary,

$\large \mathtt{\bold{Hence,}}$

$\large{ \implies}$ m<I = 180°-70° = 110°

$\large{ \implies}$ m<G = 110° since <G is opposite to <I.

ThuS,

$\large{ \implies}$ m<R = m<N = 70°

$\large{ \implies}$ $\large \underline{ \boxed{ \mathrm{ \pink{m < N = 70degree}}}}$

$\large \mathrm{ \blue{anD}}$

$\large{ \implies}$ m<I = m<G = 110°

$\large{ \implies}$ $\large \underline{ \boxed{ \mathtt{ \purple{m < G = 110degree}}}}$

Answer 2

$\huge\underline\mathrm{SOLUTION:-}$

Given:

• In a parallelogram RING, if m<R = 70°.

Need To Find:

• All the other angles.
• ∠I = ?
• ∠N = ?
• ∠G = ?

ExPlanation:

We know that,

• Adjacent angles of parallelogram is supplementary.

Then:

➠ ∠R + ∠I = 180°

➠ 70° + ∠I = 180°

➠ ∠I = 180° - 70°

➠ ∠I = 110°

But we know that,

• Opposite angles of parallelogram are equal.

Then:

➠ ∠R = ∠N

➠ 70° =∠N

➠ ∠N = 70°

And:

➠ ∠I = ∠G

➠ 110° = ∠G

➠ ∠G = 110°

ThereFore:

• ∠I = 110°
• ∠N = 70°
• ∠G = 110°

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