Question

In a parallelogram SL and SM are the height on sides PQ and QR respectively. If area of parallelogram is 21328m square and PQ= 182m and QR= 142m; find the corresponding height to the bigger and the smaller sides

Answer 1

Answer:

Given: SR=12cm, QM=7.6cm, PS=8cm.

Area of parallelogram=base×height

=12×7.6=91.2cm

2

.

Area of parallelogram=base×height

⇒91.2=8×QN

⇒QN=

8

91.2

=11.4cm.

Answer 2

ANSWER

SL

Area of parallelogram = height ×base

let the height be X

=) 21328 = X × 182

=) 21328/182=X

=) 117.18 = X

therefore height = 117.18 m

Another

SM

Area of parallelogram=height × base

Let the height be X

=] 21328 = X x 142

=] 21328/142 = X

=] 150.19 = X

Therefore height = 150.19 m

Crossponding = 19m

Thank You