Math, asked by krishnakumarroy1250, 4 months ago

in a parallelogram SL and SM are the height one sides PQand QR respectively if area of a parallelogram is 21328m2 and pQ =182m and QR 142 m find the corresponding height to the bigger and smaller sides.​

Answers

Answered by shaikquadri5566
0

Answer:

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Answered by singhyogendra559
0

Answer:

Area of parallelogram =120 cm

Area of parallelogram =120 cm 2

Area of parallelogram =120 cm 2 =15×PM

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cm

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMS

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2 +8

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2 +8 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2 +8 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2 +8 2 ⟹SM=10

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2 +8 2 ⟹SM=10 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2 +8 2 ⟹SM=10 2 −8

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2 +8 2 ⟹SM=10 2 −8 2

Area of parallelogram =120 cm 2 =15×PM⟹PM=8 cmNow in △PMSPS 2 =SM 2 +PM 2 10 2 =SM 2 +8 2 ⟹SM=10 2 −8 2 =6 cm

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