in a parallelogram the base and its corresponding altitude are in the ratio of 5:2.if the area of the parallelogram is 360 metre square find the base and altitude
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Ratio of base: Altitude = 5:2
Let x be a constant
Therefore Base is 5x
And Altitude is 2x
Now we know that area of parrallelogram is product of base and height.
Therefore ATQ
360=5x X 2x
Or x^2 = 360/10
Or x = root over 36 = 6
Therefore Base is 30m
And Height is 12m
I HOPE THIS HELPS
◀MENSURATION ▶
@sid000 #!!
Let x be a constant
Therefore Base is 5x
And Altitude is 2x
Now we know that area of parrallelogram is product of base and height.
Therefore ATQ
360=5x X 2x
Or x^2 = 360/10
Or x = root over 36 = 6
Therefore Base is 30m
And Height is 12m
I HOPE THIS HELPS
◀MENSURATION ▶
@sid000 #!!
Answered by
33
Hey!
Let the values be x and y
Base= 5x
Altitude=2x
Area= 360 m^2
Let's find the base and altitude,
Area of a parallelogram= bh
360=5x*2x
360=10x^2
360/10=x^2
36=x^2
x=√36
x= 6 m
Base= 5*6=30m
Height=2*6=12m
Hope it helps...!!!
Let the values be x and y
Base= 5x
Altitude=2x
Area= 360 m^2
Let's find the base and altitude,
Area of a parallelogram= bh
360=5x*2x
360=10x^2
360/10=x^2
36=x^2
x=√36
x= 6 m
Base= 5*6=30m
Height=2*6=12m
Hope it helps...!!!
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