In a parallelogram the base and its crossponding altitude are in the ratio 5:2 if the area of the parallelogram is 360m2 find base and altitude
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Hey mate...here is ur ans..☺☺✌
Let the base be 5x and altitude be 2x
Area = 360m^2
Area of parallelogrm = l × b
360 = 5x × 2x
360 = 10x^2
x^2 = 360/10
So x = 6
base = 5x = 5 × 6 = 30
altitude = 2x = 2×6 = 12
Hope it helps u....thanks...☺☺✌
Let the base be 5x and altitude be 2x
Area = 360m^2
Area of parallelogrm = l × b
360 = 5x × 2x
360 = 10x^2
x^2 = 360/10
So x = 6
base = 5x = 5 × 6 = 30
altitude = 2x = 2×6 = 12
Hope it helps u....thanks...☺☺✌
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