Question

In a parallelogram the base and its crossponding altitude are in the ratio 5:2 if the area of the parallelogram is 360m2 find base and altitude

Answer 1

Hey mate...here is ur ans..☺☺✌

Let the base be 5x and altitude be 2x
Area = 360m^2

Area of parallelogrm = l × b

360 = 5x × 2x

360 = 10x^2

x^2 = 360/10

$x = \sqrt{36} \\ \\ x = 6$

So x = 6

base = 5x = 5 × 6 = 30
altitude = 2x = 2×6 = 12

Hope it helps u....thanks...☺☺✌