Math, asked by leela6453, 9 months ago

In a parking place the parking charges of 5 cars and 4 scooters is rs 37 and parking charges of 6 cars and 3 scooters is rs 39

Answers

Answered by Anonymous
5

let cars be x and scooters be y

therfore ,

BTQ,

       5x + 4 y = 37.....eq. (1)

and, 6x + 3y = 39.....eq.(2)

mutiplying eq. 1 with 3

  ''               ''  . 2  ''    4

therefore 24x + 12y = 156

        and  15x + 12y = 111

            (-)       (-)    

--------------------------------------------------

                9x             = 45

                  x             = 45/9 = 5 = therefore  5 Rs parking charges per car

Now,

       putting value of  x in eq. 1

we get,  5 x + 4y = 37

              5 * 5 + 4y = 37

             25 + 4y = 37

                      4y = 37-25 =12

                        y = 12/4 = 3 = therefore  3 rs parking charges per scooter  

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