Question

In a particular Assembly Constituency election only 2 candidates contested. 90% of the voter's cast their votes in the election. The winning candidate secured 60% of the total votes polled and won by a majority of 27000 votes. Find the no of votes in the voters list.​

Answer 1

Answer:

Let total number of voters be x

Winning candidate=60% of votes=60/100x

Losing candidate= Total votes-votes of losing candidate=90-60=30%

Losing candidate=30% of votes= 30/100x

Majority= 27000

Majority=Winning-Losing

27000= 60/100x-30/100x

27000=30/100x

27000*100/30=x

x=2700000/30

x=90000

Hence, total number of voters=90000

Answer 2

Answer:

Let total number of voters be x

Winning candidate=60% of votes=60/100x

Losing candidate= Total votes-votes of losing candidate=90-60=30%

Losing candidate=30% of votes= 30/100x

Majority= 27000

Majority=Winning-Losing

27000= 60/100x-30/100x

27000=30/100x

27000*100/30=x

x=2700000/30

x=90000

Hence, total number of voters=90000