In a particular grating, the sodium doublet is viewed in
third order at 10.2° to the normal and is barely resolved.
Find (a) the ruling spacing and (b) the total width of
grating.
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Answer:
ANSWER
(a) From dsinθ=mλ we find
d=
sinθ
mλ
avg
=
sin10
∘
3(589.3nm)
=1.0×10
4
nm=10μm
(b) The total width of the ruling is
L=Nd=(
m
R
)d=
mΔλ
λ
avg
d
=
3(589.59nm−589.00nm)
(589.3nm)(10μm)
=3.3×10
3
μm=3.3mm
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