Question

In a particular reaction 4KJ of heat is released by the system and 8KJ of work is done on system determine ∆U​

Answer 1

Answer:

Answer:−

Solution : According to the first law of

thermodynamics

∆U = Q + W

Q = -2 kJ, W = +6 kJ

∆U = -2 kJ + 6 kJ = + 4 kJ

Qp = ∆H = - 2kJ