In a particular reaction 4KJ of heat is released by the system and 8KJ of work is done on system determine ∆U
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Answer:−
Solution : According to the first law of
thermodynamics
∆U = Q + W
Q = -2 kJ, W = +6 kJ
∆U = -2 kJ + 6 kJ = + 4 kJ
Qp = ∆H = - 2kJ
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