Question

in a particular system the unita of lenth mass and time are chosen to be 10 cm,10g and 0.1s respectively. The unit of force in this system will be equal to?

Answer 1

Here,
Length or distance =10cm=10/100=0.1m
Mass=10g=10/1000=0.001kg
Time=0.1s
Now,
Force=ma
=m*l/t
=0.001*0.1/0.1
=0.001N

Answer 2

Answer:

The unit of force in this system will be equal to 0.1N.

Explanation:

The given system has different sets of unit defined parameter, therefore the unit of force will also change accordingly, which can be given by –

Given data suggest that, 1 unit of length l = 10 cm

1 unit of mass m = 10 g

1 unit of time t = 0.1 s

Thereby, as we know the unit of force = N

And, $\bold{1 N=1 k g \frac{m}{s^{2}}}$

Therefore F = mass×$\bold{\frac{\text {length}}{t i m e^{2}}}$

$\begin{aligned} F &=\frac{m l}{t^{2}} \\ F &=10 \times 10^{-3} \times 10 \times \frac{10-2}{(10-1)^{2}} \\ F &=100 \times \frac{10^{-3-2}}{10^{-2}} \\ F &=\frac{10^{-3}}{10^{-2}} \\ F &=10^{-1} \end{aligned}$

F = 0.1 N