Math, asked by sharmilrana363, 1 year ago

In a partnership a invest 1/6 of the capital for 1/6 of the time, b invest 1/3 of the capital for 1/3 of the time and c the rest of the capital for the whole time out of a profit of rs 4600 b share is

Answers

Answered by VEDULAKRISHNACHAITAN
15

Answer:

Rs 800

Step-by-step explanation:

Hi,

Let 'x' be the total capital invested

Given that 1/6 of the capital is invested by a,

hence 'a's investment is x/6 for T/6 of time,

hence Total value of a's investment for period T/6 will be xT/36

Given that 1/3 of the capital is invested by b,

hence 'b's investment is x/3 for T/3 of time

hence Total value of b's investment for period T/3 will be xT/9

Rest of the investment is done  by c

hence 'c's investment is x - x/3 - x/6 = x/2 for period of T

hence Total value of c's investment for period of T will be xT/2

Profit should be divided on the total value of investment for period of T

which is (xT/36 + xT/9 + xT/2) = 23xT/36

Hence b's share should be (xT/9)/(23xT/36) = 4/23 rd

Hence profit received by b = 4/23*4600 = Rs 800

Hope, it helped !


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