Math, asked by purushottam50, 1 year ago

In a party, if 1 out of every 3guests brought bouquets, 1 out of 5 guests brought gift items, 1 out of 6 gave cash gifts and the remaining 27 guests gave gift vouchers and none of them gave two things. How many people attended the party?​

Answers

Answered by uzmaperwaiz
3

Step-by-step explanation:

people brought bouquets = 1 out of 3

=3+1=4

people brought gift items = 1 out of 5

=1+5=6

people gave cash gifts = 27

35 people

Answered by gadakhsanket
29

Dear Student,

◆ Answer -

90 guests

● Explanation -

Let x be total no of guests who attended the party.

No two guests gave two things.

Guests bringing bouquets = x/3

Guests bringing gift items = x/5

Guests bringing cash gifts = x/6

Guests bringing gift vouchers = 27

So now, total guests are calculated as -

x = x/3 + x/5 + x/6 + 27

x = 10x/30 + 6x/30 + 5x/30 + 27

x = 21x/30 + 27

x - 7x/10 = 27

3x/10 = 27

x = 27 × 10/3

x = 90 guests

Therefore, 90 people attended the party.

Thanks dear. Hope this helps you..

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