Question

in a party only couples are invited. if 44*4/9% of invited people are vegetarian and 60% of males are non vegetarian,then find the number of fathers,if 20% males have children(it is given that 920 women are non vegetarian)​

Answer 1

Consider x be the number of couples,

So, the number of males = x, females = x,

Total persons invited = x + x = 2x

Percentage of vegetarian people out of total guests = $44\frac{4}{9}\%$

Thus, the total vegetarian people = $44\frac{4}{9}\%\text{ of }2x$

                                                          $=\frac{\frac{400}{9}\times 2x}{100}$

                                                          $=\frac{8x}{9}$

Also, 60% males are vegetarian,

Thus, vegetarian males = 60% of x

                                        $=\frac{60x}{100}$

                                        $=\frac{3x}{5}$

Non vegetarian females = total vegetarian people - vegetarian males

$=\frac{8x}{9}-\frac{3x}{5}$

According to the question,

$\frac{8x}{9}-\frac{3x}{5}=920$

$\frac{40x-27x}{45}=920$

      $13x=920\times 45$

         $x=\frac{41400}{13}\approx 3185$

That is, number of males is 3185.

Now, 20% males have children,

Thus, number of fathers = 20% of total males

                                         $=\frac{20}{100}\times 3185$

                                         $=\frac{1}{5}\times 3185$

                                         $=637$

Therefore, there would be 637 fathers.

Answer 2

Answer:

360

fraction value of 44*4/9% = 4/9

let multiply by 100 = 400/900

let,

400= vegetarian

900 = total people in party

total non- vegetarian= 900-400= 500

fron total people equal number of male and female

450 male and 450 female

60% of 450= 270 total males non-vegetarian

female non-vegetarian = 500-270= 230

230 unit= 920 unit

1 unit = 920/230= 4

total males = 450*4 =1800

20% of 1800= 360 are number of fathers

answer is "360"