Question

In a pcm system the step size is 2v if the step size is reduced to 0.25v the quantiazation noise power decreases by a factor?
4,16,32,64

Answer 1

Answer:

im here to find out the answer,but this website is forcing me write the answer which im not aware of . sry for the lame answer

Explanation:

Answer 2

Answer:

64

Explanation:

Mean squared Quantization noise power  ∝ $q_s^2$ . Where, $q_s$ is step size.

So if step size is reduced from 2v to 0.25 v, i.e, become 1/8 of the previous one

⇒ Noise power will become 1/64 times, aka decreased by a factor of 64.

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