Question

In a pentagon, a) How many diagonals can be drawn from a vertex to other vertices. b) How many triangles will be made by the diagonals? c) What is the sum of angles of a pentagon?




Answer fast ​

Answer 1

$\huge\red{ANSWER}$

A)Each vertex has two diagonals, so if you counted each diagonal from every vertex twice, you might think there were 10 diagonals.

B}A triangle has no diagonals. A square has two diagonals of equal length, which intersect at the center of the square. The ratio of a diagonal to a side is. A regular pentagon has five diagonals all of the same length.

c}540°

540°FAQs on Sum of Angles in a Polygon

540°FAQs on Sum of Angles in a PolygonFor example, to find the sum of interior angles of a pentagon, we will substitute the value of 'n' in the formula: S=(n-2) × 180°; in this case, n = 5. So, (5-2) × 180° = 3 × 180°= 540°.

Answer 2

Answer:

ANSWER

A)Each vertex has two diagonals, so if you counted each diagonal from every vertex twice, you might think there were 10 diagonals.

B}A triangle has no diagonals. A square has two diagonals of equal length, which intersect at the center of the square. The ratio of a diagonal to a side is. A regular pentagon has five diagonals all of the same length.

c}540°

540°FAQs on Sum of Angles in a Polygon

540°FAQs on Sum of Angles in a PolygonFor example, to find the sum of interior angles of a pentagon, we will substitute the value of 'n' in the formula: S=(n-2) × 180°; in this case, n = 5. So, (5-2) × 180° = 3 × 180°= 540°.

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