in a pentagon ABCDE,BC II ED and Angle B: angle A angle E= 3:4:5
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Given In a pentagon A B C D E, AB is parallel to DC and<A:<E:<D=3:4:5 find angle E
AB is parallel to DC. sum of interior angles of the transversal is 180 degree. B + C = 180 degree. Also sum of interior angles is equal to 540 degree
Let A = 3 x, E = 4 x and D = 5 x
So angle A + B + C + D + E = 540
B + C + A + D + E = 540
180 + 3 x + 4 x + 5 x = 540
180 + 12 x = 540
12 x = 540 - 180
12 x = 360
x = 360 / 12
x = 30 degree
So angle E = 4 x = 4 x 30 = 120 degree
Angle E = 120 degree
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