Question

In a pentagon ABCDE, BL I Ac , CM I AD, EN I AD. Also, Bl=6cm, CM = 10cm, EN=7cm, AC=12cm, AD = 14cm. Find the area of pentagon ABCDE​

Answer 1

Answer:

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Step-by-step explanation:

Area of pentagon ABCDE= Area of ΔABC+ Area of ΔACD+ Area of ΔADE

Here , BL⊥AC,CM⊥AD,EN⊥AD

So, BL, CM and EN perpendiculars to ΔABC,ΔACD and ΔADE respectively.

Area of triangle with perpendicular =1/2×base×height

∴ Area of ΔABC=1/2×AC×BL

Area of ΔACD=1/2×AD×CM

Area of ΔADE=1/2×AD×EN

Now area of pentagon ABCDE=1/2AC×BL+1/2×AD×CM+1/2×AD×EN

=(1/2×10×3)+(1/2×12×7)+(1/2×12×5)

=15+42+30

=87

Answer 2

Answer:

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Step-by-step explanation:

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