in a pentagon interior angles measures 80°,90°,90° and 3x and exterior angle is x find the angle measure of x
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Answered by
1
Answer:
Step-by-step explanation:
Sum of all interior angles of quadrilateral =360
0
∴50+130+120+x=300
x=60
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(b)
90+a=180
a=90
Sum of all angles of quad =360
x+70+60+90=360
x=140
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(c)
70+a=180 (Linear pair)
a=110
60+b=180 (Linear pair)
b=120
Sum of measures of all angles of pentagon =540
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∴120+110+x+x+30=540
2x=280
x=140
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(d)
Sum of all angles of pentagon 540
Given all angles are equal
∴5x=540
x=108
0
Answered by
0
Answer:
Step-by-step explanation:
80+90+90+x+3x=36360
260+4x = 360
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