in a pentagon two angles are 40 degree and 60 degree and the rest are in ratio 1 : 3 : 7 find the biggest angle of the Pentagon . ANS : 280°
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60°+40°+x+3x+7x=540
100°+11x=540
11x=540°-100°
11x=440°
x=40°
x=40°,3x=120° and 7x=280°
100°+11x=540
11x=540°-100°
11x=440°
x=40°
x=40°,3x=120° and 7x=280°
bijay9852527295:
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Answered by
34
Here Two Angles Given 40° and 60°
Let other 3 angles are x, 3x, 7x (The ratio is 1:3:7)
We know that Sum of all interior angles of a pentagon = 540
∴ x + 3x + 7x + 40 + 60 = 540
11x + 100 = 540
11x = 440
x = 40
∴ Desired angles are
x = 40
3x = 3×40 = 120
7x = 7×40 = 280
Hence Largest Angle is 280°
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