Math, asked by Naimur, 1 year ago

in a perfectly symmetrical distribution the mode and the mean are 42 and 49 respectively approximate median and distribution is _a) 47. b)48. c)49. d)50

Answers

Answered by abhi178
2
we know,
\boxed{\boxed{\text{mode}\pm2\text{mean}=3\text{median}}}

Given in a perfectly symmetrical distribution,
the mode = 42
and the mean = 49
we have to find approximate value of the median.
so, \text{mode}\pm2\text{mean}=3\text{median}

42 ± 2 × 49 = 3 × median

42 - 2 × 49 = 3 × median [ ignored ]

=> 42 + 2 × 49 = 3 × median

=> 42 + 98 = 3 × Median

=> 140/3 = median

median = 46.67 ≈ 47

hence, answer is option (a).


Answered by mysticd
0

Given ,


Mode = 42 ,


Mean = 49 ,


Median = ?


By Empharical Formula ,


Mode = 3×median - 2×mean


42 = 3 × median - 2 × 49


=> 42 = 3 × median - 98


=> 42 + 98 = 3 × median


=> 140 = 3 × median


=> Median = 140/3


Medain = 46.666...

≈ 47


Option ( A ) is correct.


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