in a perfectly symmetrical distribution the mode and the mean are 42 and 49 respectively approximate median and distribution is _a) 47. b)48. c)49. d)50
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we know, ![\boxed{\boxed{\text{mode}\pm2\text{mean}=3\text{median}}} \boxed{\boxed{\text{mode}\pm2\text{mean}=3\text{median}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Ctext%7Bmode%7D%5Cpm2%5Ctext%7Bmean%7D%3D3%5Ctext%7Bmedian%7D%7D%7D)
Given in a perfectly symmetrical distribution,
the mode = 42
and the mean = 49
we have to find approximate value of the median.
so,![\text{mode}\pm2\text{mean}=3\text{median} \text{mode}\pm2\text{mean}=3\text{median}](https://tex.z-dn.net/?f=%5Ctext%7Bmode%7D%5Cpm2%5Ctext%7Bmean%7D%3D3%5Ctext%7Bmedian%7D)
42 ± 2 × 49 = 3 × median
42 - 2 × 49 = 3 × median [ ignored ]
=> 42 + 2 × 49 = 3 × median
=> 42 + 98 = 3 × Median
=> 140/3 = median
median = 46.67 ≈ 47
hence, answer is option (a).
Given in a perfectly symmetrical distribution,
the mode = 42
and the mean = 49
we have to find approximate value of the median.
so,
42 ± 2 × 49 = 3 × median
42 - 2 × 49 = 3 × median [ ignored ]
=> 42 + 2 × 49 = 3 × median
=> 42 + 98 = 3 × Median
=> 140/3 = median
median = 46.67 ≈ 47
hence, answer is option (a).
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