Question

in a photoelectric emission the stopping potential is plotted against the frequency (v) of incident light . The resulting curve is a straight line which makes an angle theta with the v-axis that tan theta will be equal to
a)h/e
b)e/h
c)-(wf)/e
d)eh/(wf)

where wf is work function
h is planks constant
e is charge of electron
please solve it anyone...

Answer 1

We know that,

E = wf + K.E

K.E = E - wf

= hn - wf

eV° = hn - wf

V° = hn/e - wf/e

[ y = mx + c ] ( Slope Form of Straight Line )

m= Slope Of Line = Tan0 = h/e

Hence, Option (i) is correct.


Hope it Helps!