In a plane there are 28 points, out of which 8 points are collinear. How many Quadrilaterals can we make from these points?
Options
21375
20349
19475
19285
Answers
Answered by
2
Answer:
19475
i hope itz correct
Answered by
0
Answer: 19285 (D)
Step-by-step explanation:
Taking 1 point from those collinear points and rest 3 from non collinear
8C1 + 20C3 (t1)
Taking 2 point from those collinear points and rest 2 from non collinear
8C2 + 20C2 (t2)
Taking 4 points from non collinear points
20C4 (t3)
ans = t1+t2+t3 = 19285
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