Math, asked by deepakvish6244, 10 months ago

In a plane there are 28 points, out of which 8 points are collinear. How many Quadrilaterals can we make from these points?
Options

21375

20349

19475

19285

Answers

Answered by rehankhan07
2

Answer:

19475

i hope itz correct

Answered by hotshot399
0

Answer:  19285 (D)

Step-by-step explanation:

Taking 1 point from those collinear points and rest 3 from non collinear

8C1 + 20C3 (t1)

Taking 2 point from those collinear points and rest 2 from non collinear

8C2 + 20C2 (t2)

Taking 4 points from  non collinear points

20C4 (t3)

ans = t1+t2+t3 = 19285

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