Question

in a plane there were 12 points out of this 7 points are collinear and 5 points are non collinear find the probability of getting pentago frm non collinear points i a plane?

Answer 1

Answer:

no. of point in a plane =12

no. of point in collinear =5

to draw a line two points are required 

if no. three points are collinear they

 no of lines = 12C2

Since 5 points are collinear, using these 5

 points we can draw only one line 

∴ the no. of different lines =12C2−5C2+1

(single line using collinear points)

=12C2−5C2+1 

=66−10+1

=57

please mark brainlist

Answer 2

Answer:

Number of different lines = 57.

Step-by-step explanation:

Given:

12 points out of this 7 points are collinear and 5 points are non collinear.

To find:

the probability of getting pentagon from non collinear points is a plane.

Step 1

Number of point in a plane = 12

Number of point in collinear = 5

To draw a line two points stand required

If number three points stand collinear.

Number of lines = 12C2

Step 2

Since 5 points are collinear, using these 5

points we can draw only one line

Therefore, the number of different lines

$=12C_{2} -5C_{2} +1$

(single line using collinear points)

= 66 − 10 + 1

= 57

Number of different lines = 57.

#SPJ2