Question

in a planet, mass and radius both are found to be double than of earth. calculate value of acceleration due to gravity on its surface( g is 9.8 m s2)​

Answer 1

Answer:

Here's your answer

Explanation:

Given that,

Mass of the earth =M

Radius of the earth = R

We know that,

g=GM/R²

Now, mass and radius is double

 g′=G2M​/4R²

g′=GM​/2R²

g′=1/2​g

Hence, the acceleration due to gravity on the surface of a planet is 1/2​g.

Hope you understand.

Answer 2

Answer:

4.9m/s²if you found it helpful plz mark it as brainliest

it gives me motivation to add more answers like this

Explanation:

we know that

g=GM/R²

given

M=2$M_{e}$

R=2$M_{e}$

9.8=G$M_{e}$/$R_{e}$²

g=GM/R²

 =(G2$M_{e}$)/4$M_{e}$²

  =1/2(9.8)

   =4.9m/s²

if you found it helpful plz mark it as brainliest

it gives me motivation to add more answers like this