Question

In a ∆ POD ,if 3 p =4 o =6 D calculate the angles

Answer 1

Let,
3p=4o=6d=(x)°
So,
p=(x/3)°
o=(x/4)°
d=(x/6)°

We know that, sum of all angles of a Δ=180°
=(x/3)°+(x/4)°+(x/6)°=180°
=x/3+x/4+x/6=180
=4x+3x+2x/12=180
=9x/12=180
=x=180*12/9
=x=240
Hence,
P=(240/3)°=80°
O=(240/4)°=60°
D=(240/6)°=40°

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