In a polygon there are 12 diagonals through a vertex . How many diagonals are there in all
Answers
Answer:90
Step-by-step explanation:
You exclude adjacent sides will drawing diagonals so the polygon is 15 sided.
No.of diagonals=no.of sides[(no.of sides-3)/2]
=15[(15-3) /2]
=15[12/2]
=15*6
=90
Given,
In a polygon, the number of diagonals presents from a single vertex = 12
To find,
The total number of diagonals in the polygon.
Solution,
We can simply solve this mathematical problem using the following process:
Mathematically,
In any polygon;
total number of vertices = total number of sides
{Equation-1}
And, the total number of diagonals in a n-sided polygon = n(n-3)/ 2
{Equation-2}
According to the question;
The polygon has 12 diagonals present from a single vertex
=> The polygon has 12 points to which a single point has its diagonals
=> Total number of vertices in the polygon
= total number of points to which a single point has its diagonals + the common vertex itself + 2 adjacent vertices which firm the corresponding adjacent sides
= 12 + 1 + 2 = 15
=> Total number of vertices in the polygon = 15
=> Total number of sides in the polygon = 15
(according to equation-1)
Now, according to the equation-2;
The total number of diagonals in the given polygon having number of sides, n equal to 15 is
= n(n-3)/ 2
= 15 × (15-3)/2
= 15 × 12/2
= 15 × 6 = 90
Hence, the polygon has a total of 90 diagonals.