Question

In a population of 5000 individuals is 450 individuals show a recessive trait.What will be no.Of heterozygous individuals in this population

Answer 1

The number of individuals with the heterozygous trait would be 2100

Explanation:

• The total population is 5000. The no-of individuals for recessive trait are 450.

• Now, According to Hardy-Weinberg Equation:

• 5000/400= 0.09

• And q= 0.3

• p+q = 1       p - 0.3 = 1=> P= 0.7

• And 2pq = 2× 0.7×0.3= 0.21×2= 0.42

• Hence 2pq = 0.42× 5000= 2100

• So, the number of individuals with the heterozygous trait would be 2100

Answer 2

Explanation:

2100 is the right answer.............