Question

In a population of 8000,80people can not recognize the taste of phenylthiocarbamide . Find out the number of homozygous tasters

Answer 1

Answer:

7920

Explanation:

8000-80

Done.^_^

Answer 2

Answer:

Explanation:

"Genetic taster of PTC is TT or Tt and non taster are tt.

So, 80 people out of 8000 are genetic non-tasters

So the frequency of non taters are 0.01 tt

Here we will use hardy Weinberg equilibrium q2 = 0.01

Therefore, q= 0.1

p + q = 1

p = 1 – 0.1 = 0.9

hence, p = 0.9

therefore, p2 = 0.9 x 0.9 = 0.81 is the frequency of homozygous tasters.

So, here the overall population is 8000 and as calculated frequency of homozygous is 0.81.

So number of homozygous taster is x/8000 = 0.81

X = 0.81 x 8000= 6480

Thus homozygous taster are 6480 "