Question

in a population of guinea pigs. in hardy- weinberg equilibrium, 364 have rough hair( dominant), and the allelic frequency for rough hair is 0.7 . find out the total number of population, if the gene in reference has only two alleles (1) 108 (2) 120 (3) 324 (4) 400 please explain with solution ​

Answer 1

Answer:

because

Explanation:

From Hardy-Weinberg equilibrium, p + q = 1,

q = 1 – p = 1 – 0.7 = 0.3

q2 =0.3 *0.3=0.09

The homozygous dominant individuals are represented by

1600 *p =1120

1600*q=144

So, the correct option is '144'

Answer 2

heyyy.❤

➡➡➡From Hardy-Weinberg equilibrium, p + q = 1,

q = 1 – p = 1 – 0.7 = 0.3

q2 =0.3 *0.3=0.09

The homozygous dominant individuals are represented by

1600 *p =1120

1600*q=144

So, the correct option is '144'➡➡