Question

In A POR, If PQ > PR and bisectors of ZQ and ZR
intersect at S. Show that SQ > SR.​

Answer 1

Answer:

In △PQR,PQ>PR

⇒∠PRQ>∠PQR(Angle opposite to longer side is greater)

⇒

2

1

∠PRQ>

2

1

∠PQR

⇒∠SRQ>∠SQR since RS and QS are the bisectors of ∠PRQ and ∠PQR

In △SQR,∠SRQ>∠SQR

⇒SQ>SR since side opposite to greater angle is longer.