Question

In A POR. NM | RQ 11
PN
MIRR I PM = 15. MO
10. NR = 8. then find nq


M
(2)
ND
In A MNP, ZMNP = 90°, seg NQ I se
ZMNP = 90°, seg NQ I seg MP. If MQ = 9,
QP = 4, then find NQ.​

Answer 1

Answer:

We know that,

In a right angled triangle, the perpendicular segment to the hypotenuse from the opposite vertex, is the geometric mean of the segments into which the hypotenuse is divided.

∴ QN²=MQ×QP

=9×4

QN=√ 36

=√ 36

=6

Hence, NQ = 6.