Question

In A POR, P is right angle. If PQ-10 cm and PR=24 cm, Find QR.​

Answer 1

Answer:

by using pythogoras

Step-by-step explanation:

( hypotenuse) 2 = ( perpendicular) 2 + ( base) 2

( hypotenuse) 2 = ( perpendicular) 2 + ( base) 2 (hypotenuse) 2 = ( 24 ) 2 + ( 10 ) 2

( hypotenuse) 2 = ( perpendicular) 2 + ( base) 2 (hypotenuse) 2 = ( 24 ) 2 + ( 10 ) 2 (h) 2 = 576 + 100

( hypotenuse) 2 = ( perpendicular) 2 + ( base) 2 (hypotenuse) 2 = ( 24 ) 2 + ( 10 ) 2 (h) 2 = 576 + 100 ( h) 2 = 676

( hypotenuse) 2 = ( perpendicular) 2 + ( base) 2 (hypotenuse) 2 = ( 24 ) 2 + ( 10 ) 2 (h) 2 = 576 + 100 ( h) 2 = 676 ( h ) = √676

( hypotenuse) 2 = ( perpendicular) 2 + ( base) 2 (hypotenuse) 2 = ( 24 ) 2 + ( 10 ) 2 (h) 2 = 576 + 100 ( h) 2 = 676 ( h ) = √676 h = 26

Qr = 26 CM

Answer 2

Answer:

26

Step-by-step explanation:

<p=90*

PQ=10

PR=24

$QR^{2}$=$PR^{2}$ + $PQ^{2}$

$QR^{2}$= $24^{2}$ + $10^{2}$

$QR^{2}$= 576+100

$QR^{2}$ = 676

QR=$\sqrt676$

QR=26