in a positive number of two digits the sum of the digits is 15 if the digit are interchanged the number increased by 9 find the number
Answers
Let the two no's be x and y
x+y=15 (1)
10x+y=10y+x-9
10x-x=10y-y-9
9x=9y-9
x=9y-9/9
x=y-1
x-y=-1 (2)
x+y=15
x-y=-1
2x=14
x=14/2=7
x+y=15
7+y=15
y=15-7=8
x=7
y=8
The number is 78.
Given:
Sum of two digits = 15
Interchanged number is increased = 9
Solution:
Let, x = units digit
y = tens digit
So, the number can be expressed = 10y + x ⇒ 1
The number if the digits are reversed = 10x + y ⇒ 2
One equation be: x + y = 15 ⇒ 3
The equation 1 is equal to sum of increased value while interchanged number and equation 2.
10x + y = 10y + x + 9 ⇒ 4
↓
10x - x = 10y - y +9
↓
9x - 9y = 9 ⇒ 5
Divide the equation 5 by 9.
x - y = 1 ⇒ 6
move -y on right side
x = 1 + y ⇒ 7
substitute equation 7 in equation 3
x + y = 15
1+y + y = 15
1+2y=15
2y= 15-1
y= 15/2
y=7 ⇒ 8
substitute equation 8 in equation 3
x + 7 = 15
x=15-7
x=8 ⇒ 9
Since, x = units digit
y = tens digit
Therefore, The number is 78.
The sum of 8 and 7 is 15 and 87 is 9 more than 78.