In a potato race a bucket is placed at a starting point which is 5m from the first potato, and the other potatoes are placed 3m apart in a straight line. There are ten potatoes in the line. A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick the next potato, runs to the bucket and drop it in, and she continues in the same way until all the potatoes are in the bucket. How far does the competitor run when she finish picking the fifth potato? What is the total distance the competitor has to run? can i have a FILA table example of this question?
Answers
Answer:
Step-by-step explanation:
A1=2x5=10
A2=2x(5+3)=16
A3=2x(5+3+3)=22
S10=10/2(2x10+(10-1)6)
=5(20+9x6)
=5x(20+54)
=5x74
S10=370
So the answer is 370
I hope this will help you
Answer:
Step-by-step explanation:
Solution :-
Since, distance between the first and potato and the bucket = 5 m.
and also there are 10 potatoes which are 3 m apart.
Distance covered by the competitor is first pick,
= 2 × 5 = 10 m.
Distance covered by the competitor in second pick,
= 2 × (5 + 3 × 1) = 2 × 8 = 16 m
Distance covered by the competitor in third pick,
= 2 × (5 + 3 × 2)
= 2 × (5 + 6)
= 64 m
Similarly, distance covered by the 10th pick.
= 2 × (5 + 3 × 9)
= 2 × (5 + 27)
= 64 m.
Therefore, the sequence becomes,
10, 16, 22, ..........., 64
Let S be the total distance covered by the competitor.
i.e,
S = 10 + 16 + 22 + ..... + 64
Here,
a = 10, d = 16 - 10 = 6
n = 10, l = 64
Therefore, S(10) = 10/2[10 + 64]
= 5 × 74
= 370 m
Hence, the total distance covered by the competitor is 370 m.
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