in a potentiometer arrangement a cell of EMF1.20 Vgive the balance point at 30 cm length of wire if the cell is replaced by another cell and the balance point shift to 65 cm what is the EMF of the second cell
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E2/E1=L2/L1=65/30
=E2=65/30E1
=65/30×1.2
=2.6V
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