Physics, asked by aburewatkar207, 1 year ago

In a potentiometer arrangement for determining the internal resistance of a cell,the balance point of the cell in open circuit is 350 cm. Whwn a resistance of 9 ohm is used in the external circuit of the cell, the balanced point shift to 300 cm . Determine the internal resistance of the cell.

Answers

Answered by Anonymous
4

⭐⭐⭐ Hey mate!!⭐⭐⭐

__________________________________________________________


Let,


° r = internal resistance


° L1 = initial balancing length


° L2= final balancing length


° Now apply formula,


° r = (L1-L2)/L2 × R


° r = (350-300)/300 ×9


° ✓ r = 1.5 ohm


Hope it will help you...✌️✌️


# phoenix ⭐

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