In a potentiometer arrangement for determining the internal resistance of a cell,the balance point of the cell in open circuit is 350 cm. Whwn a resistance of 9 ohm is used in the external circuit of the cell, the balanced point shift to 300 cm . Determine the internal resistance of the cell.
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⭐⭐⭐ Hey mate!!⭐⭐⭐
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Let,
° r = internal resistance
° L1 = initial balancing length
° L2= final balancing length
° Now apply formula,
° r = (L1-L2)/L2 × R
° r = (350-300)/300 ×9
° ✓ r = 1.5 ohm
Hope it will help you...✌️✌️
# phoenix ⭐
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